[F. 2 Maths] Factorization (2 questions)
1.) 1 - 14a + 49a^2
2.) 3 ( 7x - 3 )^2 + 4 ( 7x - 3 ) - 15
Please show your working steps clearly.
[F. 2 Maths] Factorization (2 questions)
2007-08-31 6:27 am
回答 (3)
2007-08-31 6:36 am
✔ 最佳答案
1) 1 - 14a + 49a^2 =(7a)^2 -14a +1^2
=(7a-1)^2
2)LET (7x - 3 )^2 BE A,
3 ( 7x - 3 )^2 + 4 ( 7x - 3 ) - 15
= 3 A^2 + 4 A - 15
= (3A-5)(A+3)
2007-08-31 6:35 am
1.) 1 - 14a + 49a^2 = 1 - 2*(1)(7a) + (7a)^2
= (1-7a)^2
OR (7a-1)^2
2.) 3 ( 7x - 3 )^2 + 4 ( 7x - 3 ) - 15
=[3(7x-3)-5][(7x-3)+3]
=(21x-9-5)(7x)
=(21x-14)(7x)
=49x(3x-2)
= (1-7a)^2
OR (7a-1)^2
2.) 3 ( 7x - 3 )^2 + 4 ( 7x - 3 ) - 15
=[3(7x-3)-5][(7x-3)+3]
=(21x-9-5)(7x)
=(21x-14)(7x)
=49x(3x-2)
參考: me
收錄日期: 2021-04-13 15:25:38
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070830000051KK05962