maths
2007-08-30 8:43 am
if the sum of three consecutive odd intergers is greater than 87,find the least possible integer.Let x be the smallest integer.
回答 (3)
2007-08-30 8:49 am
✔ 最佳答案
Let x be the smallest integer, then the other 2 are x + 2 and x + 4 respectively. Then,
x + ( x + 2 ) + ( x + 4 ) > 87
3x + 6 > 87
3x > 81
x > 27
Hence the least possible integers of x is 29, and the other two numbers are 31 and 33 respectively.
參考: My Maths Knowledge
2007-08-30 8:51 am
x+x+2+x+4>87
3x+6>87
3x>81
x>27
THE LEAST POSSIBLE INTERGER IS 29
3x+6>87
3x>81
x>27
THE LEAST POSSIBLE INTERGER IS 29
參考: MYSELF
2007-08-30 8:51 am
Let x be the smallest integer,
then the three consecutive odd intergers are x, x+2, x+4
x+x+2+x+4 > 87
3x+6>87
3x>81
x>27
Therefore, the least possible integer is 29
2007-08-30 00:52:39 補充：
So, the three consecutive numbers are 29, 31,33
then the three consecutive odd intergers are x, x+2, x+4
x+x+2+x+4 > 87
3x+6>87
3x>81
x>27
Therefore, the least possible integer is 29
2007-08-30 00:52:39 補充：
So, the three consecutive numbers are 29, 31,33
參考: 自己
收錄日期: 2021-04-23 20:32:31
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