1.The HCF and LCM of two number are 6 and 108 respectively.If the two numbers are
12 and x, finds (Hint:x is a multiple of 6 and a factor of 108)
2.There are two numbers. Neither of them is a multiple of the ofther. Find two pairs of
possible values of the numbers if their H C F is 16
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有2條數學問題呀~ 小6-中1 ge 作業
2007-08-30 12:13 am
回答 (2)
2007-08-30 12:35 am
✔ 最佳答案
有條咁既公式: HCFxLCM = 該兩數相乘所以 12x=HCFxLCM=6x108=648
x=54
(2) HCF 係 16 , 即是一定係16的倍數
只要這兩個倍數的倍是互質,即是沒有任何公因數(除1)便可以了
所以 16x2 , 16x3 : 32, 48
或 16x3 , 16x4: 48, 64 這兩pair 便可以了
2007-08-29 16:42:52 補充：
(1) 18一定不是答案, 因為12 和18的LCM 是36, 不是題目所說的108
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