It is given that the areas of trapeziums A1B1C1D1, A2B2C2D2 , A3B3C3D3 , A4B4C4D4 , A5B5C5D5, ....isa sequence.
(a) If the areas of traqpeziums A1B1C1D1, A2B2C2D2 and A3B3C3D3are (36)cm^2 , (144)cm^2 and (576)cm^2 respectively, the area of trapezium A4B4C4D4 = ___________
(b)How many times is the area of trapezium A6B6C6D6to that of trapezium A1B1C1D1?[show your working]
數學問題(10分)
2007-08-29 5:32 am
回答 (1)
2007-08-29 6:18 am
✔ 最佳答案
areas of traqpeziums A1B1C1D1= 36cm^2 = (6)^2areas of traqpeziums A2B2C2D2=144cm^2 = (12)^2
areas of traqpeziums A3B3C3D3=576cm^2 = (24)^2
Hence,
(a) areas of traqpeziums A4B4C4D4=(48)^2 = 2304cm^2
(b) areas of traqpeziums A5B5C5D5=(96)^2 = 9216cm^2
area of trapezium A6B6C6D6 = (192)^2 = 36 864cm^2
area of trapezium A6B6C6D6to that of trapezium A1B1C1D1 = 36864/6=6144
2007-08-28 22:20:02 補充：
(b) should be 36864/36 = 1024
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