數學問題(10分)
2007-08-29 5:01 am
It is given that the 'n'th term of a seqaunce is n^2+3. Is the difference between any two consecutive terms of the sequence a constant? Explain the answer.
回答 (2)
2007-08-29 5:13 am
✔ 最佳答案
T(n+1)-T(n) = (n+1)^2 + 3 - (n^2+3) =n^2+2n+1+3-n^2-3
= 2n + 1,
which depends on n.
Hence, the difference between two terms is NOT a constant
參考: me
2007-08-29 5:10 am
T(n) = n^2+3
T(n+1) = (n+1)^2+3 = n^2+2n+4
T(n+1) - T(n) = 2n+1
T(n+1) = (n+1)^2+3 = n^2+2n+4
T(n+1) - T(n) = 2n+1
收錄日期: 2021-04-13 13:10:15
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