請幫我計下喱幾條數

2007-08-29 12:07 am
代數:
1.2x+3x²+x-2x²
2.8x+4/2-(3x-2)
3.5(a-1)/2 - 4(a+1)/3

負數:
1.(-2)² (-3)
2.(-1)(-2)²
3.(-3)² (+4)²/(-6)²
4.(-32)(-9)/(-36)+(-4)(-6)/(+2)

回答 (2)

2007-08-29 12:30 am
✔ 最佳答案
代數:
1. 2x+3x²+x-2x²
= 3x²-2x²+2x+x
= x²+3x

2. 8x+4/2-(3x-2)
= 8x+4/2-3x+2
=8x-3x+4/2+2
=5x+4

3. 5(a-1)/2 - 4(a+1)/3
= 15(a-1)/6-8(a+1)/6
= 15(a-1)-8(a+1)
= 15a-15-8a-8
= 7a-7

負數:
1. (-2)² (-3)
= 4(-3)
= -12

2. (-1)(-2)²
= (-1)(4)
= -4

3. (-3)² (+4)²/(-6)²
= 9x16/36
= 144/36
= 4

4. (-32)(-9)/(-36)+(-4)(-6)/(+2)
= 288/(-36)+24/2
= -8+12
= 4
參考: me=]
2007-08-29 2:33 am
代數:
1.2x+3x²+x-2 = 3x+x²
2.8x+4/2-(3x-2) = 5x=4
3.5(a-1)/2 - 4(a+1)/3 =7a-7

負數:
1.(-2)² (-3) =-12
2.(-1)(-2)² =-4
3.(-3)² (+4)²/(-6)² =4
4.(-32)(-9)/(-36)+(-4)(-6)/(+2) =4
參考: me


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