中一升中二暑期作業有D唔識~
可5可以幫幫我~
1. Find the percentage decrease in each of the following cases:
(a) A decrsase form 60 to 45. (b) A decrease form $8 to $6.
2. The monthly salary of an engineer is $9,500.This is increased by 8% after a year.By how much is his monthly salary increased in the second year?
幫幫我
中一升中二暑期作業有D唔識~
2007-08-27 6:12 pm
回答 (3)
2007-08-27 6:16 pm
✔ 最佳答案
1a, (60-45)/60 * 100% = 25%1b, (8-6)/8 * 100% = 25%
2, 9500* 8% = 760
2007-08-27 10:18:07 補充：
1, 記住個percentage decrease = difference / original price * 100%
2007-08-27 6:22 pm
1a (60-45)/45X100%=33/1/3%
1B (8-6)/6X100%=33/1/3%
2a the salary of next year:9500 X (1+8%)=10260
the salary of the second year:10260 X (1+8%)=11080.8
how much his salary increased:11080.8-9500=1580.8
應該係咁......
2007-08-27 12:57:18 補充：
SOR~打錯咗係新減舊/舊1a (60-45)/60X100%=25%1B (8-6)/8X100%=25%
1B (8-6)/6X100%=33/1/3%
2a the salary of next year:9500 X (1+8%)=10260
the salary of the second year:10260 X (1+8%)=11080.8
how much his salary increased:11080.8-9500=1580.8
應該係咁......
2007-08-27 12:57:18 補充：
SOR~打錯咗係新減舊/舊1a (60-45)/60X100%=25%1B (8-6)/8X100%=25%
2007-08-27 6:20 pm
1.a.(60-45)/60*100%=25%
b.(8-6)/8*100%=25%
2.$9,500*8%=$760
2007-08-27 10:23:34 補充：
sorry!!!頭先打錯~1.a.(60-45)/60*100%=25% b.($8-$6)/$8*100%=25%2.$9,500*8%=$760
b.(8-6)/8*100%=25%
2.$9,500*8%=$760
2007-08-27 10:23:34 補充：
sorry!!!頭先打錯~1.a.(60-45)/60*100%=25% b.($8-$6)/$8*100%=25%2.$9,500*8%=$760
參考: me
收錄日期: 2021-04-13 19:31:39
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https://hk.answers.yahoo.com/question/index?qid=20070827000051KK00947