Simplify

2007-08-27 8:00 am
Given x>y>0, then (x^y X y^x) / (y^y X x^x) =

回答 (2)

2007-08-27 8:26 am
✔ 最佳答案
x^y X y^x
-------------
y^y X x^x

= y^(x-y) X x^(y-x)

= y^(x-y) X x^[-(x-y)]

y^(x-y)
= ----------
x^(x-y)

y x
= (------) ^ (x-y) OR (--------) ^ (y-x)
x y

2007-08-27 00:28:08 補充:
 y^(x-y)= ---------- x^(x-y)  y        x= (------) ^ (x-y) OR (--------) ^ (y-x)  x       y
2007-08-27 8:05 am
= y/x

2007-08-27 14:39:27 補充:
I simply miscalculated, please neglect my answer.


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