http://i102.photobucket.com/albums/m99/aauu2006/2.jpg
plz help~~~~~
how to solve it? 關於 開方根
2007-08-27 5:51 am
回答 (1)
2007-08-27 6:07 am
✔ 最佳答案
[rt(x)+x]/[1+x+rt(x)] = [rt(x)+x]/[1+x+rt(x)]* [1+x-rt(x)]/[1+x-rt(x)]=[rt(x)+x][1+x-rt(x)] / [(1+x)^2 -(rt(x))^2]
=rt(x)+xrt(x)-x+x+x^2-xrt(x) / (1+x+x^2)
=[x^2+rt(x)]/(1+x+x^2)
參考: me
收錄日期: 2021-04-13 13:09:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070826000051KK04530