math 三角比的關係

2007-08-26 1:34 am
化簡:
(sin r - cos r) (sin r - cos r) + 2sin r cos r

回答 (2)

2007-08-26 1:43 am
✔ 最佳答案
(sin r - cos r) (sin r - cos r) + 2sin r cos r
=(sin r - cos r) ^2+ 2sin r cos r
=sin^2r-2sin r cos r +cos^2r+ 2sin r cos r
=1
參考: me
2007-08-26 1:48 am
answer is 1 !

http://hk.knowledge.yahoo.com/question/?qid=7007082502243
←can anyone help me??


收錄日期: 2021-04-23 21:09:55
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