f.2 maths x 1 (20 marks)
回答 (3)
2007-08-24 5:34 am
(x+1)(2x-3) & (x-2)(x+1)的L.C.M.=(x+1)(2x-3) & (x-2)(x+1)的L.C.M.
參考: me!!!
2007-08-24 5:33 am
(x+1)(2x-3)(x-2)
收錄日期: 2021-04-23 19:29:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070823000051KK05668