f.2 maths x 1 (20 marks)

[匿名]

2007-08-24 5:29 am

(x+1)(2x-3) & (x-2)(x+1)的L.C.M.

回答 (3)

David

2007-08-24 5:32 am

✔ 最佳答案

LCM=(x+1)(2x-3)(x-2)

參考: me

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Shi Hang

2007-08-24 5:34 am

(x+1)(2x-3) & (x-2)(x+1)的L.C.M.=(x+1)(2x-3) & (x-2)(x+1)的L.C.M.

參考: me!!!

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kai

2007-08-24 5:33 am

(x+1)(2x-3)(x-2)

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