maths
回答 (1)
2007-08-23 6:43 am
✔ 最佳答案
(logx³- logy) / (log¹/x + log ³√y) = (3logx – logy) / (-logx + (1/3)logy)
= (3logx – logy) / [(-3logx + logy)/3]
= -(3logx – logy) / [(3logx - logy)/3]
= -3
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