maths

2007-08-23 6:38 am
Simplify logx³- logy / log¹/x + log ³√y

回答 (1)

2007-08-23 6:43 am
✔ 最佳答案
(logx³- logy) / (log¹/x + log ³√y)
= (3logx – logy) / (-logx + (1/3)logy)
= (3logx – logy) / [(-3logx + logy)/3]
= -(3logx – logy) / [(3logx - logy)/3]
= -3


收錄日期: 2021-04-13 13:03:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070822000051KK06030

檢視 Wayback Machine 備份