畢氐定理(pythagoras'ｔｈｅｏｒｅｍ）

底部既對角線(diagonal)=√(8^2+8^2)
=√128

由頂點垂直落泥會將對角線除2
=√128 / 2
=2(√ 8)

(12)^2 + (2(√ 8))^2 = x^2
144+32=x^2
x=13.27/13.3

ps. √=開方

如果你真係要用筆寫返既..我建議你自己設ABCD...係啲點到...會方便好多

Is it regular?
Consider the base
Hyp= (8^2+8^2)^0.5
=8(2)^0.5
Consider the right side perpendicular to the base with x
x=[(Hyp/2)^2+12^2]^0.5
x=13.266....
x=13.3(3sig fig)

2007-08-21 19:37:49 補充：
Hyp is Hypotenuse

2007-08-21 19:38:18 補充：
I have steps and if you do not understand, please write there.

2007-08-21 19:38:56 補充：
8(2)^0.5=128^0.5

X=13.26649916

x=13.266