題目：
Factorize
8(a²-a)^3+42(a²-a)²-36a²+36a
要有步驟。
Factorize 急急急！
2007-08-21 8:24 am
回答 (2)
2007-08-21 8:49 am
✔ 最佳答案
=8(a2-a)^3+42(a2-a)^2-36(a2-a)=2(a2-a)[4(a2-a)^2+21(a2-a)-18]
=2a(a-1)[4(a2-a)-3][(a2-a)+6]
=2a(a-1)[(a2-a)+6][4a2-4a-3]
=2a(a-1)(a²-a+6)(2a+1)(2a-3)
參考: my knowledge
2007-08-21 8:36 am
8(a²-a)^3+42(a²-a)²-36a²+36a
=8a^6-8a^3+42a^4-42a^2-36a^2+36a
=8a^6+42a^4-8a^3-78a^2+36a
=8a^3(a^3-1)+6a(7a^3-13a+6)
I am not sure if it isn't correct.Anyway,I hope I can really help you.^^
=8a^6-8a^3+42a^4-42a^2-36a^2+36a
=8a^6+42a^4-8a^3-78a^2+36a
=8a^3(a^3-1)+6a(7a^3-13a+6)
I am not sure if it isn't correct.Anyway,I hope I can really help you.^^
收錄日期: 2021-04-13 13:02:47
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070821000051KK01044