The follwing have 4 questions , can u help me to slove it ? thanks
(Do not just give me the ans , i need the process )
1. Factorize ax-2by-2bx+ay
2.Factorize 20u^2 - 16v(3v-u)
3.Factorize (x^2 + 2x + 3) ^2 - 13( x^2 +2x +3) +22
4.Factorize (x^2 + 4)^2 - (x^2 +4)x -20x^2
Maths question (F.3) about factorize
2007-08-21 5:41 am
回答 (2)
2007-08-21 6:12 am
✔ 最佳答案
1. ax - 2by - 2bx + ay
= a(x+Y) - 2b(x+y)
= (a-2b)(x+y)
2.
20u^2 - 16v(3v-u)
= 4(5u^2-12v^2+4vu)
= 4(5u-6v)(u+2v)
3.
(x^2+2x+3)^2 - 13(x^2+2x+3) + 22
= [(x^2+2x+3)-2][(x^2+2x+3)-11]
= (x^2+2x+1)(x^2+2x-8)
=(x+1)^2(x+4)(x-2)
4.
(x^2+4)^2 - (x^2+4)x - 20x^2
= (x^2+4+4x)(x^2+4-5x)
=(x+2)^2(x-1)(x-4)
參考: Own Calculation
2007-08-21 5:55 am
ax-2by-2bx+ay
=a(x+y)-2b(x+y)
=(a-2b)(x+y)
20u^2 - 16v(3v-u)
=20u^2-48v^2+16uv
=(4u+8v)(5u-6v)
(x^2 + 4)^2 - (x^2 +4)x -20x^2
=(x^2+4+4x)(x^2+4-5x)
=a(x+y)-2b(x+y)
=(a-2b)(x+y)
20u^2 - 16v(3v-u)
=20u^2-48v^2+16uv
=(4u+8v)(5u-6v)
(x^2 + 4)^2 - (x^2 +4)x -20x^2
=(x^2+4+4x)(x^2+4-5x)
參考: myself
收錄日期: 2021-04-13 20:01:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070820000051KK05490