the area of a parallelogrem is equal to the area of a triangle.the height of the triangle
is15cm.if two figures have the same base
find the heightof the parallelogram
let the height of the parallelogram be h cm and bases be b cm
方程計
中一數學......
2007-08-18 9:42 pm
回答 (5)
2007-08-18 9:51 pm
✔ 最佳答案
Area of a triangle: 15b/2 Area of a parallelogram: hb
Area of a triangle = Area of a parallelogram
So, hb = 15b/2
2hb = 15b
2hb /b = 15
2h = 15
h = 7.5
2007-08-18 10:08 pm
Let the height of the parallelogram be h cm and the base be b cm
=> hb=15b/2
hb=7.5b
h=7.5b/b
h=7.5
The height of the parallelogram is equal to 7.5.
=> hb=15b/2
hb=7.5b
h=7.5b/b
h=7.5
The height of the parallelogram is equal to 7.5.
2007-08-18 9:57 pm
The area of parallelogram : h x b (cm2)
The area of triangle : (15 x b)/ 2 (cm2)
b x h = (15 x b) /2
(b x h) / b = [(15 x b)/2] / b
h = 15 / 2
h = 7.5cm
so the high of parallelogram be 7.5cm
work hard on maths !!! add oil !!
The area of triangle : (15 x b)/ 2 (cm2)
b x h = (15 x b) /2
(b x h) / b = [(15 x b)/2] / b
h = 15 / 2
h = 7.5cm
so the high of parallelogram be 7.5cm
work hard on maths !!! add oil !!
參考: 自己
2007-08-18 9:48 pm
b x h = 15b/2
h = 15/2
hence the height of the parallelogram is 15/2 (7.5).
h = 15/2
hence the height of the parallelogram is 15/2 (7.5).
2007-08-18 9:48 pm
let the height of the parallelogram be h cm and bases be b cm
Parallelogram area = hb
Triangle area = 0.5*height*b (as they have same base)
= 0.5(15)b
= 7.5b
7.5b = hb
Therefore, h = 7.5
b can be any value.
Parallelogram area = hb
Triangle area = 0.5*height*b (as they have same base)
= 0.5(15)b
= 7.5b
7.5b = hb
Therefore, h = 7.5
b can be any value.
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