m2次-n2次的因式分解?
回答 (3)
2007-08-17 8:03 pm
✔ 最佳答案
m^2-n^2=(m+n)(m-n)
because
(m+n)(m-n)
=m*m-mn+mn-n*n
-mn+mn=0
so
(m+n)(m-n)
=m*m-n*n
=m^2-n^2
參考: my brain
2007-08-17 7:32 pm
m^2 - n^2
=(m + n)(m - n)
2007-08-17 11:35:27 補充：
覆數(m n)(m - n)= m^2 mn - mn - n^2= m^2 - n^2
=(m + n)(m - n)
2007-08-17 11:35:27 補充：
覆數(m n)(m - n)= m^2 mn - mn - n^2= m^2 - n^2
收錄日期: 2021-04-13 12:58:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070817000051KK01403