FORM TWO MATHS (2)

2007-08-16 10:41 pm
4. Convert the following decimal numbers into hexadecimal numbers.
(a) 59(10)
(b) 428(10)

5. Convert the following binary numbers into decimal numbers.
(a) 11010 ( 2)
(b) 1010111 (2)

6. Convert the following hexadecimal numbers into binary numbers.
(a) 18A ( 16)
(b) ABC ( 16)


7. Write the following numbers in expanded form.
(a) 1057(10)
(b) 110101(2)
(c) 1A2B3C(16)

回答 (1)

2007-08-17 12:13 am
✔ 最佳答案
4.
用短除就可以計到, 或用Windows 內置的小算盤開啟工程模式
(a)
59=3B

16 | _59_ ------ B
3
(b)
428
16 | _428_ ----- C
16 | _26_ ----- A
1

5.
(a) 11010
= 1*2^3 + 1*2^2 + 0 + 1*2^1 + 0
= 26

(b) 1010111
= 1*2^6 + 0 + 1*2^4 + 0 + 1*2^2 + 1*2^1 + 1
= 87

6.
可以將佢拆開每一個字一part, 一個一個解做binary, 順序放埋一齊就得.
(a)
18A
1 8 A
0001 1000 1010

18A = 110001010

(b)
ABC
A B C
1010 1011 1100
ABC = 101010111100

7.
(a)
1057(10)
=1*10^3 + 0*10^2 + 5*10^1 + 7*10^0

(b) 110101(2)
= 1*2^5 + 1*2^4 + 0 + 1*2^2 + 0 + 1*2^0

(c) 1A2B3C(16)
= 1*16^5 + A*16^4 + 2*16^3 + B*16^2 + 3*16^1 + C*16^0
參考: Self


收錄日期: 2021-04-13 13:17:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070816000051KK02793

檢視 Wayback Machine 備份