A and B are two consecutive numbers( B< A ) . HAlf of B exceeds one-fourth of A by 1.Find the values of A and B.
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2007-08-16 9:57 pm
回答 (2)
2007-08-16 10:08 pm
✔ 最佳答案
One similar Qs is asked before...A = B + 1--------(1)
1/2 B = 1/4 A + 1
B = 1/2A + 2-------- (2)
Sub (2) into (1),
A = B + 1
A = (1/2A + 2) + 1
A = 1/2A + 3
1/2A = 3
A = 6
Sub A = 6 into (1),
A = B + 1
6 = B + 1
B = 5
Thus, A = 6 and B = 5
2007-08-16 10:08 pm
B/2 = A/4 +1
as B+1 = A, so
B/2 = (B+1)/4 + 1
2B = (B+1) + 4
2B = B + 5
B = 5
A = 6
as B+1 = A, so
B/2 = (B+1)/4 + 1
2B = (B+1) + 4
2B = B + 5
B = 5
A = 6
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