數學問題(三角形)(10分)!

2007-08-15 6:36 pm
A triangle with vertices (1,1), (1,-2),(5,-2).
Find the coordinates of the centroid of the above triangle.

回答 (3)

2007-08-15 7:02 pm
✔ 最佳答案
coordinates of x = (1+5)/2 = 3

coordinates of y = (1+[-2])/2 = -0.5

therefore coordinates of the centroid is (3,-0.5)

Shadow.
2007-08-16 5:09 pm
coordinates of x = (1+5)/2 = 3

coordinates of y = (1+[-2])/2 = -0.5

2007-08-16 09:10:43 補充:
三角形,平面幾何之一基本形也,乃三線段相接所成者。其線段曰邊,其交曰點,二邊於形內交處所成之角曰內角。三角形悉以內角歸類。若三角均為銳角,謂銳角三角形;有一直角者,謂直角三角形;有一鈍角者,謂鈍角三角形。內角和恆為二直角,故無多於一直角或銳角者。又有殊者,即二或三邊等長也。若二邊等長,謂等腰三角形;三邊皆等長,則謂等邊三角形。
2007-08-15 6:44 pm
the units of (1,1)and(1,-2)
1-(-2)
=3 units
the units of (1,-2)and(5,-2)
5-1
=4units
the coordinates of the centroid of the above triangle
3x4/2
=6 sq.units
參考: ~myself~


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