數學(簡單)  10!

2007-08-14 9:26 pm
分解為因式:

1) a^2+6a+9=? 呢d題我唔係好識6a應該點做..
6a對條題目有咩影響..係咪唔使理?

2) 81-(2x-3y)^2=?

3) (2x-y)^2-x^2=?

thz!步驟.
更新1:

請加以解釋!

更新2:

^2=2次方

回答 (2)

2007-08-14 9:45 pm
✔ 最佳答案
1) a^2+6a+9 = ?
a^2+6a = -9
a(^2+6) = -9
a = -9/(^2+6)

2) 81-(2x-3y)^2 = ?
(2x-3y)^2 = 81
2x-3y = 81/^2

3) (2x-y)^2-x^2 = ?
(2x-y)^2 = x^2
2x-y = x^2/^2
2x-y = x
2x-x = y
1x = y

其實,呢d係咩數呀......究竟係每條要求咩代數都唔講清楚...
我都唔明有咩簡單...
我盡量俾d step你...
仲有想問...^..這個符號係咪要跟住前面果個家...
可以既話就補充下啦...good luck!
參考: 自己諗
2007-08-14 9:55 pm
6a coeficient is 6.
6/2=3

so 1) (a+3)^2
6a can be used to determine the base of the final answer.


2) (9+2x-3y)(9-2x+3y)

3) (2x-y+x)(2x-y-x)
=(3x-y)(x-y)

OR

(2x-y)^2-x^2
=4x^2-4xy+y^2-x^2
=3x^2-4xy+y^2
=(3x-y)(x-y)

(The first method should be better.)
參考: my brain


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