paul bought a eletronic game at $750 and sold it to John at a profit of 20%.Later,John sold the game to George.
(a) How much did John pay to Paul?
(b)If George paid $60 more than Paul,what is the profit/loss percentage of John?
I want to ask Maths
2007-08-14 1:58 am
回答 (4)
2007-08-14 2:11 am
✔ 最佳答案
(a) The amount of money that John paid to Paul=$750 x (1+20%)
=$900
(b)i The amount of money that paid by George
=$750+$60
=$810
The percentage loss of John
= (900-810)/ 900 x100%
=10%
參考: ME
2007-08-14 2:08 am
a 750X(1+20%)=$900
b % change=[(750+60-900)/900]X100%
=-10%
The loss percentage is 10%
b % change=[(750+60-900)/900]X100%
=-10%
The loss percentage is 10%
2007-08-14 2:07 am
a)750 x (1+20%)=900
b)9%
2007-08-13 18:08:18 補充：
90/810 x 100%
b)9%
2007-08-13 18:08:18 補充：
90/810 x 100%
2007-08-14 2:06 am
(a) the profit made by Paul is 750*20%=150
therefore, John pay Paul 750+150=900
(b) george paid $60 more than Paul, so george paid 750+60=810
Therefore, John made a loss of 900-810=90
Percentage Loss= (Loss/Cost)*100%
the percentage loss of John is (90/900)*100%=10%
therefore, John pay Paul 750+150=900
(b) george paid $60 more than Paul, so george paid 750+60=810
Therefore, John made a loss of 900-810=90
Percentage Loss= (Loss/Cost)*100%
the percentage loss of John is (90/900)*100%=10%
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