Maths送分題~~~萬分感激 thx.

2007-08-13 11:58 pm
化簡下列各題:
1). 6x-15/3x-3 + 4x+1/2-2x
2). 6x/3x^2+3x + x-1/2(x+1)^2 - x/6x^2-6
仲有我想問點樣通分母?

萬分感激 thx.

回答 (1)

2007-08-14 12:05 am
✔ 最佳答案
1). 6x-15/3x-3 + 4x+1/2-2x
= 6x-15/3(x-1) + 4x+1/2(1-x)
=6x-15/3(x-1) + 4x+1/-2(x-1)
=6x-15/3(x-1) - 4x+1/2(x-1)
=12x-30 / 6(x-1) - 12x+3/6(x-1)
=-27/6(x-1)
=-9/2(x-1)//

6x/3x^2+3x + x-1/2(x+1)^2 - x/6x^2-6
=6x/3x(x+1) + x-1/2(x+1)(x+1) - x/6(x^-1)
=6x/3x(x+1) + x-1/2(x+1)(x+1) - x/6(x-1)(x+1)
=12x(x-1)/6x(x+1)(x-1)+3x-3/6(x+1)(x-1)-x/6(x+1)(x-1)
=(12x^2-12x+3x-6-x)/6x(x+1)(x-1)
=(12x^2-10x-6)/6x(x+1)(x-1)
=(6x^2-5x-3)/3x(x+1)(x-1)//


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