1.求一個圓周為24pi cm的圓形之面積。
2.某扇形之半徑為10cm,面積為40pi cm^2。求扇形之周界。
3.某扇形的半徑為6cm,周界為20cm。求扇形角,答案準確至最接近度。
4.一個圓柱體的底面積為16pi,且它的體積為80pi。它的總表面積為
求積法:圓形,圓柱體,扇形
2007-08-13 2:58 am
回答 (3)
2007-08-13 3:20 am
✔ 最佳答案
1. 半徑 = 12面積S = 12^2pi = 144pi cm^2
2. 弧長 = 40pi x 2 /10 = 8pi cm
扇形之周界 = 20 + 8pi cm
3. 弧長 = 20 - 12 = 8 cm
扇形角 = 8/6 = 4/3弧度 = 76度
4. 高h = 5 cm
周界 = 8pi cm
總表面積 = 16pi x 2 + 5 x 8pi = 72pi cm^2
2007-08-13 3:23 am
1)144pi sq.cm
2)8pi cm
3)191
4)I think your question is not yet finished.
2)8pi cm
3)191
4)I think your question is not yet finished.
2007-08-13 3:13 am
1. (24/2)^2pi cm^2=144pi cm^2
2. (40/(10x10))x10x2pi + (10x2)
=(8pi+20) cm
3. ((20-6-6) /(6x2pi))x360
= 114.591559度
= 115度
4. (80/16)x(16^-2)X2pi+16pi+16pi
=40pi+16pi+16pi
=72pi cm^2
2. (40/(10x10))x10x2pi + (10x2)
=(8pi+20) cm
3. ((20-6-6) /(6x2pi))x360
= 114.591559度
= 115度
4. (80/16)x(16^-2)X2pi+16pi+16pi
=40pi+16pi+16pi
=72pi cm^2
收錄日期: 2021-04-20 18:35:53
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