點解(u-1)(u+3)-(u+3)=0
會等於(u-1-1)(u+3)=0?
maths question
2007-08-12 9:22 pm
回答 (2)
2007-08-12 9:40 pm
✔ 最佳答案
抽common factor, 因為第一式有兩個(u+3) (係一樣既野)抽佢離剩翻(u-1)同 -1<<< lee 個本身痴住後面既(u+3)
最後變成
(u+3) [(u-1)-1]
再combine翻變
(u-1-1)(u+3)
2007-08-12 9:38 pm
(u-1)(u+3)=u+3
u-1=(u+3) / (u+3)
u-1=1
u=2
(2 - 1 - 1) (2 + 3) = 0
0 x 5 = 0
u-1=(u+3) / (u+3)
u-1=1
u=2
(2 - 1 - 1) (2 + 3) = 0
0 x 5 = 0
收錄日期: 2021-04-23 17:10:38
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https://hk.answers.yahoo.com/question/index?qid=20070812000051KK01899