(1)志森繞著一個長40m,闊30m的長方形運動場跑了12圈。問他共跑了多少米?
(2)志強推著一個半徑為35cm的滾輪行了396m,問滾輪&共轉動了多少周?(取22/7)
(3)在一個個周界為31.4m的圓形水池外圍,築了一條闊度為1m的環形路徑。求該路徑的外圍長度。
(4)若有一個長10cm,闊5cm,高6cm的長方體,若要從長方體切割出一個最大的正方體,所得的正方體的體積是多少?
周界,面積數學問題?
2007-08-12 5:51 am
回答 (5)
2007-08-12 5:56 pm
✔ 最佳答案
(1) (40+30)x2x12 = 70x2x12 = 140x12 =1680.'.他共跑了1680米
(2) 396m = 39600cm
39600÷(35x2x22/7) = 39600÷(70x22/7) = 39600÷220 = 180
.'.滾輪&共轉動了180周
(3) (31.4÷3.14+2)x3.14 = (10+2)x3.14) = 12x3.14 = 37.68
.'.路徑的外圍長度是37.68m
(4) 5x6x5 = 125
.'.所得的正方體的體積是125cm3
2007-08-12 6:43 am
1.(40+30)*2*12
=1680m
2.396*100/2/(22/7)/35
=180
3.(31.4/2/3.14+1)*2*3.14
=37.68m
4.5*5*5
=125
=1680m
2.396*100/2/(22/7)/35
=180
3.(31.4/2/3.14+1)*2*3.14
=37.68m
4.5*5*5
=125
2007-08-12 6:33 am
(1)(40+30)*2*12=1680m
(2)396*100/2/(22/7)/35=180
(3)(31.4/2/3.14+1)*2*3.14=37.68m
(4)5*5*5=125
(2)396*100/2/(22/7)/35=180
(3)(31.4/2/3.14+1)*2*3.14=37.68m
(4)5*5*5=125
2007-08-12 6:23 am
(1) (40+30)x2x12=1680m
(2) (396x100)除(35x2x22/7)=180[because志強推著一個半徑為35cm的滾輪行了396< >,問滾輪&共轉動了多少周?(取22/7)]
(3)How to caculate without 取 22/7 or 3.14?But if you 取 3.14,it must be:
{(31.4除3.14除2)+1}x3.14=18.84 (取22/7)
(4)5x5x5=125(cm3)
(2) (396x100)除(35x2x22/7)=180[because志強推著一個半徑為35cm的滾輪行了396< >,問滾輪&共轉動了多少周?(取22/7)]
(3)How to caculate without 取 22/7 or 3.14?But if you 取 3.14,it must be:
{(31.4除3.14除2)+1}x3.14=18.84 (取22/7)
(4)5x5x5=125(cm3)
2007-08-12 5:58 am
(1)2x(40m+30m)x12=140x12=1680m
(2)369x100除(35cmx2x22/7)
(3)~~
(2)369x100除(35cmx2x22/7)
(3)~~
收錄日期: 2021-05-03 11:36:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070811000051KK05436