1.若k是一個雙數,2個僅大於k的連續單數的和是多少?以代數式表示出來。
2.子樂有4張$20紙幣,他用款項的65%買了2個玩具車,平均每個玩具車售多少元?
3.商店內每部相機的標價是3200元,現以2720元出售,即相等於多少折優惠?
4.凡於今天到餅店買蛋糕,便可得到買四送一的優惠,即相等以多少折出售?
5.生先生本月獲加薪6%,加薪後的月薪是9010元。他原本的月薪是多少元?
6.商店內每部電腦以3690元出售,虧蝕了18%。求每部電腦的成本。
數學題~~急急急~~
2007-08-12 12:57 am
回答 (3)
2007-08-12 7:12 am
1 k+1+k+3
=2k+4
2 4X20X65%/2
=$26
3 2720/3200X100%=85%(85折)
It is sold at 15%off (85%,85折)
4 [4/(1+4)]*100%=80%(8折)
5 9010/(1+6%)=$8500
6 3690/(1-18%)=$4500
=2k+4
2 4X20X65%/2
=$26
3 2720/3200X100%=85%(85折)
It is sold at 15%off (85%,85折)
4 [4/(1+4)]*100%=80%(8折)
5 9010/(1+6%)=$8500
6 3690/(1-18%)=$4500
2007-08-12 1:33 am
1.k+1+k+3=(k+k)+(1+3)=2k+4
2.20x4x65%/2=80x65%/2=80/20x13/2=4x13/2=52/2=26(元)
3.100-3200/2720x10~100-1.18x10~100-11.8~88.2~88(折)
4.4/(4+1)=4/5=0.8=80%=8(折)
5.9010/(100+6)x100=9010/106x100=8500(元)
6.3690/(100-18)x100=3690/82x100=45x100=4500(元)
I wish I could help you.
2007-08-11 17:36:21 補充：
3.should be 2720/3200x100=0.85x100=85(折)
2.20x4x65%/2=80x65%/2=80/20x13/2=4x13/2=52/2=26(元)
3.100-3200/2720x10~100-1.18x10~100-11.8~88.2~88(折)
4.4/(4+1)=4/5=0.8=80%=8(折)
5.9010/(100+6)x100=9010/106x100=8500(元)
6.3690/(100-18)x100=3690/82x100=45x100=4500(元)
I wish I could help you.
2007-08-11 17:36:21 補充：
3.should be 2720/3200x100=0.85x100=85(折)
2007-08-12 1:15 am
1 k+1+k+3
=2k+4
2 4*20*65%/2
=$26
3 2720/3200*100%=85%
It is sold at 15%off (85%)
4 [4/(1+4)]*100%=80%
5 9010/(1+6%)=$8500
6 3690/(1-18%)=$4500
=2k+4
2 4*20*65%/2
=$26
3 2720/3200*100%=85%
It is sold at 15%off (85%)
4 [4/(1+4)]*100%=80%
5 9010/(1+6%)=$8500
6 3690/(1-18%)=$4500
收錄日期: 2021-04-13 11:58:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070811000051KK03532