1. a(x-y)+b(x-y)
2. x(a-b)+y(b-a)
3. (a-b)^3-(a-b)^2
4. (2x-y)(a+b)+(y-2x)(a+b)
5. ax-bx+cx+cy-by+ay
唔該!!
有幾條因式分解ge題目唔識做
2007-08-11 1:51 am
回答 (2)
2007-08-11 2:04 am
✔ 最佳答案
1. a(x-y)+b(x-y)=(x-y)(a+b)
2. x(a-b)+y(b-a)
=x(a-b)-y(a-b)
=(a-b)(x-y)
3.(a-b)^3-(a-b)^2
=(a-b)^2(a-b-1)
4. (2x-y)(a+b)+(y-2x)(a+b)
=(a+b)[(2x-y)+(y-2x)]
=(a+b)(2x-y+y-2x)
=(a+b)*0
=0
5. ax-bx+cx+cy-by+ay
=(ax-bx+cx)+(cy-by+ay)
=x(a-b+c)+(ay-by+cy)
=x(a-b+c)+y(a-b+c)
=(a-b+c)(x+y)
*=乘號
參考: 我系F.4學生。
2007-08-11 2:08 am
1. a(x-y)+b(x-y)
=(a+b)(x-y)
2. x(a-b)+y(b-a)
=x(a-b)-y(a-b)
=(a-b)(x-y)
3. (a-b)^3-(a-b)^2
=[(a-b)^2‧(a-b)]-(a-b)^2
=(a-b)^2[(a-b)-1]
4. (2x-y)(a+b)+(y-2x)(a+b)
=(a+b)(2x-y+y-2x)
=(a+b)
5. ax-bx+cx+cy-by+ay
=(ax-bx+cx)+(cy-by+ay)
=x(a-b+c)+y(a-b+c)
=(a-b+c)(x+y)
2007-08-10 18:09:36 補充：
sorry,4. (2x-y)(a+b)+(y-2x)(a+b)=(a+b)(2x-y+y-2x)=0
=(a+b)(x-y)
2. x(a-b)+y(b-a)
=x(a-b)-y(a-b)
=(a-b)(x-y)
3. (a-b)^3-(a-b)^2
=[(a-b)^2‧(a-b)]-(a-b)^2
=(a-b)^2[(a-b)-1]
4. (2x-y)(a+b)+(y-2x)(a+b)
=(a+b)(2x-y+y-2x)
=(a+b)
5. ax-bx+cx+cy-by+ay
=(ax-bx+cx)+(cy-by+ay)
=x(a-b+c)+y(a-b+c)
=(a-b+c)(x+y)
2007-08-10 18:09:36 補充：
sorry,4. (2x-y)(a+b)+(y-2x)(a+b)=(a+b)(2x-y+y-2x)=0
參考: 自己
收錄日期: 2021-04-29 22:11:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070810000051KK04045