因式分解!

2007-08-10 1:23 am
1)因式分解8xy+24yz

2)因式分解abx-bcy

3)因式分解x(a-b)+y(a-b)

4)因式分解a(x-y)-b(y-x)

5)因式分解2r ^ 2+3r - 2rs -3s

6)因式分解4p^ 2+2p-8pq-4q

列明步驟.pls and thx!

回答 (2)

2007-08-10 1:28 am
✔ 最佳答案
1)因式分解8xy+24yz
8xy + 24yz
= 8y ( x + 3z)


2)因式分解abx-bcy
abx-bcy
= b (ax - cy)


3)因式分解x(a-b)+y(a-b)
x(a-b)+y(a-b)
= (a - b)(x + y)


4)因式分解a(x-y)-b(y-x)
a(x-y)-b(y-x)
= a(x-y)+b(x - y)
=(x - y)(a + b)


5)因式分解2r ^ 2+3r - 2rs -3s
2r ^ 2+3r - 2rs -3s
= 2r ^ 2- 2rs +3r -3s
= 2r ( r - s) + 3 ( r - s)
= (r - s)(2r + 3)


6)因式分解4p^ 2+2p-8pq-4q
4p^ 2+2p-8pq-4q
= 2p ( 2p + 1) - 4q ( 2p + 1)
= ( 2p + 1 ) ( 2p - 4q)
= 2 ( 2p + 1) ( p - 2q)
2007-08-10 1:55 am
8xy+24yz=8y(x+3z)
----------------------------
abx-bcy=b(a-cy)
--------------------------------------------------
x(a-b)+y(a-b)=(a-b)(x+y)
-----------------------------------------------------------------
a(x-y)-b(y-x)=a(x-y)+b(x-y)=(a+b)(x-y)
-----------------------------------------------------------------------------------------------------
2r ^ 2+3r - 2rs -3s=2r ^ 2+(3-2s)r -3s=(2r+3)(r-s)--------------十字相成法
---------------------------------------------------------------------------------------------------
4p^ 2+2p-8pq-4q=2(2p^ 2+(1-4q)p-2q)=2(2p+1)(p-2q)
參考: 提取公因式,十字相成


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