How to solve 2x(1+x二次)
回答 (3)
2007-08-10 10:17 am
✔ 最佳答案
let y = 2x(1+x^2) = 0then,
2x =0 or 1+x^2 =0
x = 0 or x^2 = -1
for x^2 = -1,
x = (-1)^(1/2) ... there is NO real root
since i = (-1)^(1/2) in complex number
therefore the ans are
x = 0 and x = i
2007-08-09 6:57 pm
2x(1+x^2)
=2x+2x^3
=2x+2x^3
2007-08-09 5:18 pm
2x( 1+ x^2)
= 2x + 2x^3
= 2x + 2x^3
收錄日期: 2021-04-29 21:44:16
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