化簡以下題目:
(xy^-1)/[(x^-2)+(y^-2)]
指數化簡問題
2007-08-07 4:31 pm
回答 (2)
2007-08-07 4:58 pm
✔ 最佳答案
(xy^-1) / [(x^-2)+(y^-2)]= (x/y) / (1/x^2 + 1/y^2)
= (x/y) / [(x^2 + y^2) / x^2y^2 ]
= x^3y^2 / [y (x^2 + y^2)]
= x^3y / (x^2 + y^2)
2007-08-09 2:12 am
(xy^-1)/[(x^-2)+(y^-2)]
=(x/y)/(1/x^2+1/y^2)
=(x/y)/[(x^2+y^2)/x^2 y^2]
=x * (x^2/y^2)/(y * (x^2+y^2))
=x^3 y/(x^2+y^2)
=(x/y)/(1/x^2+1/y^2)
=(x/y)/[(x^2+y^2)/x^2 y^2]
=x * (x^2/y^2)/(y * (x^2+y^2))
=x^3 y/(x^2+y^2)
收錄日期: 2021-04-13 00:58:21
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070807000051KK00755