(2x+3)2次方
=?
(x-5)2次方
=?
(x+2)(x-2)
=?
(3x-6)2次方
=?
詳細一點
f.2 maths(快入)
2007-08-06 11:46 pm
回答 (4)
2007-08-07 12:05 am
✔ 最佳答案
(2x+3)^2= 4x^2+12x+9
(x-5)^2
= x^2-10x+25
(x+2)(x-2)
= x^2-4
(3x-6)^2
= 9x^2-36x+36
2007-08-07 1:56 am
(2x+3)2次方=4x2次方+9
(x-5)2次方=x2次方-25
(x+2)(x-2)=x2次方-4
(3x-6)2次方=9x2次方-36
(x-5)2次方=x2次方-25
(x+2)(x-2)=x2次方-4
(3x-6)2次方=9x2次方-36
參考: ME
2007-08-06 11:57 pm
(2x+3)2次方
= 2x² + 3²
= 2x² + 9
(x-5)2次方
= x² - 5²
= x² + 25
(x+2)(x-2)
= (x)(x) + (x)(-2) + (+2)(x) + (+2)(-2)
(3x-6)2次方
= 3x² - 6²
= 3x² + 36
= 2x² + 3²
= 2x² + 9
(x-5)2次方
= x² - 5²
= x² + 25
(x+2)(x-2)
= (x)(x) + (x)(-2) + (+2)(x) + (+2)(-2)
(3x-6)2次方
= 3x² - 6²
= 3x² + 36
參考: I got distinction for the 2007 International Competitions in Australia. 唔信??? 去 http://www.eaa.unsw.edu.au 查查有冇哩樣嘢嘅存在。
2007-08-06 11:52 pm
1) 4x^2+12x+9
收錄日期: 2021-05-03 06:58:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070806000051KK02948