我想問下：
２ １
－－－＋－－－
ａ－１ １－ｘ
呢題數點計？
加以解釋！
ｔｈｚ！
數學(簡單)！
2007-08-06 7:16 pm
回答 (8)
2007-08-06 7:26 pm
✔ 最佳答案
2/(a-1) + 1/(1-x)令到分母相同先..
左面個數就(1-x)/(1-x)...因為(1-x)/(1-x)=1..所以數值無變..
右面就用番差唔多方法..之後大家分母一樣就可以分子相加..
2(1-x)/(a-1)(1-x) + 1(a-1)/(a-1)(1-x)
=(2-2x+a-1)/(a-1)(1-x)
=(1-2x+a)/(a-1)(1-x)//
2007-08-10 16:18:00 補充：
含有變數的字母....即係有未知數...a,b,c,d.......z都算係..呢條式有變數的分母有2個:a同x
2007-08-08 5:56 pm
2(1-x)/(a-1)(1-x) + 1(a-1)/(a-1)(1-x)
=(2-2x+a-1)/(a-1)(1-x)
=(1-2x+a)/(a-1)(1-x)//
=(2-2x+a-1)/(a-1)(1-x)
=(1-2x+a)/(a-1)(1-x)//
2007-08-06 8:53 pm
通分母@@
2007-08-06 7:48 pm
2(1-X)+a-1
______________
(a-1) (1-X)
=1-2x+a
_________
(a-1) (1-X)
______________
(a-1) (1-X)
=1-2x+a
_________
(a-1) (1-X)
2007-08-06 7:35 pm
令到分母相同先..
左面個數就(1-x)/(1-x)...因為(1-x)/(1-x)=1..所以數值無變..
右面就用番差唔多方法..之後大家分母一樣就可以分子相加..
左面個數就(1-x)/(1-x)...因為(1-x)/(1-x)=1..所以數值無變..
右面就用番差唔多方法..之後大家分母一樣就可以分子相加..
2007-08-06 7:26 pm
2(1-X)+a-1
______________
(a-1) (1-X)
=1-2x+a
_________
(a-1) (1-X)
通分母和進行加減, 把它化到最簡
______________
(a-1) (1-X)
=1-2x+a
_________
(a-1) (1-X)
通分母和進行加減, 把它化到最簡
2007-08-06 7:24 pm
2/a-1 + 1/1-x
=2-2x+a-1
=1-2x+a
=2-2x+a-1
=1-2x+a
收錄日期: 2021-04-12 20:49:24
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