數學(簡單)!

2007-08-06 7:16 pm
我想問下:

 2   1
---+---
a-1 1-x

呢題數點計?
加以解釋!

thz!

回答 (8)

2007-08-06 7:26 pm
✔ 最佳答案
2/(a-1) + 1/(1-x)
令到分母相同先..
左面個數就(1-x)/(1-x)...因為(1-x)/(1-x)=1..所以數值無變..
右面就用番差唔多方法..之後大家分母一樣就可以分子相加..

2(1-x)/(a-1)(1-x) + 1(a-1)/(a-1)(1-x)

=(2-2x+a-1)/(a-1)(1-x)

=(1-2x+a)/(a-1)(1-x)//

2007-08-10 16:18:00 補充:
含有變數的字母....即係有未知數...a,b,c,d.......z都算係..呢條式有變數的分母有2個:a同x
2007-08-08 5:56 pm
2(1-x)/(a-1)(1-x) + 1(a-1)/(a-1)(1-x)

=(2-2x+a-1)/(a-1)(1-x)

=(1-2x+a)/(a-1)(1-x)//
2007-08-06 8:53 pm
通分母@@
2007-08-06 7:48 pm
2(1-X)+a-1
______________
(a-1) (1-X)

=1-2x+a
_________
(a-1) (1-X)
2007-08-06 7:43 pm
3
一一一一一
1-x+1-a
3
=一一一一
2-x-a
去到lay度已經冇得計,因為你唔知嗰兩個未知數係乜.
參考: me
2007-08-06 7:35 pm
令到分母相同先..
左面個數就(1-x)/(1-x)...因為(1-x)/(1-x)=1..所以數值無變..
右面就用番差唔多方法..之後大家分母一樣就可以分子相加..
2007-08-06 7:26 pm
2(1-X)+a-1
______________
(a-1) (1-X)

=1-2x+a
_________
(a-1) (1-X)

通分母和進行加減, 把它化到最簡
2007-08-06 7:24 pm
2/a-1 + 1/1-x
=2-2x+a-1
=1-2x+a


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