1. Ann had $100. She used part of her money to buy 7 ceramic cats, in which 3 of them are more expensive than the rest by $3. If she had $7 left, how much do the two types of ceramic cat cost?
2. The cost of tea A is $30 per kg, the cost of tea B is $20 per kg. If w kg of tea A and (w+1)kg of tea B are mixed together, and the cost of the mixed tea is $24 per kg. Find w.
求救!2條equation問題
2007-08-02 11:17 pm
回答 (4)
2007-08-02 11:24 pm
✔ 最佳答案
1.Let the cost of the cheaper cat be $x3(x+3)+4x=100-7
7x=84
x=12
∴The cost of the two types of ceramic cat are $12 and $15
2.30w+20(w+1)=24(w+w+1)
50w+20=48w+24
w=2
2007-08-02 11:31 pm
1.
Let the 2 types be A and B,
100-(3A+4B)=7
3A-3=4B
by substitution, CAT type A: $11.25, CAT type B: $16
Let the 2 types be A and B,
100-(3A+4B)=7
3A-3=4B
by substitution, CAT type A: $11.25, CAT type B: $16
參考: ／
2007-08-02 11:30 pm
1.
let x be the number of the cheaper ceramic cat.
3x + (3x+3) = 100-7
6x + 3 = 93
x= 15
one type of the ceramic cat cost $15 and the other cost 15+1= $16
2.
30w + 20(w+1)= 24
50w = 24- 20
w= 4/50
w= 0.08 kg
let x be the number of the cheaper ceramic cat.
3x + (3x+3) = 100-7
6x + 3 = 93
x= 15
one type of the ceramic cat cost $15 and the other cost 15+1= $16
2.
30w + 20(w+1)= 24
50w = 24- 20
w= 4/50
w= 0.08 kg
參考: 自己計
2007-08-02 11:21 pm
1. Let x be the cost of one type of rat, x+3 be another type.
(x+3)*3 + x*4 + 7 = 100
solve it yourself.
2. (30*w + 20* (w+1) ) / (w+w+1) = 24
solve it yourself.
(x+3)*3 + x*4 + 7 = 100
solve it yourself.
2. (30*w + 20* (w+1) ) / (w+w+1) = 24
solve it yourself.
參考: my knowledge
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