64m二次n二次-(m+n)二次
ans係(8mn-m-n)(8mn+m+n)
我想要步驟及知點解
我將(m+n)二次分成(m+n)(m+n)
之後就唔識做....
唔知點將64m二次n二次同分左果段合埋...
數學...因式分解及恆等式
2007-08-02 4:57 pm
回答 (3)
2007-08-02 5:09 pm
✔ 最佳答案
64(m^2)(n^2) - (m+n)^2=(8mn)^2-(m+n)^2
=(8mn+m+n)(8mn+m+n) <
2007-08-02 09:10:05 補充：
by considering a^2-b^2=(a b)(a-b) where a=8mn b=m n
2007-08-02 09:10:33 補充：
by considering a^2-b^2=(a b)(a-b) where a=8mn b=m ndamn system
2007-08-02 09:12:06 補充：
by considering a^2-b^2=(a b)(a-b) where a=8mn b=m n
2007-08-02 5:55 pm
64m^2n^2 - (m+n)^2
= (8mn)^2 - (m+n)^2
= (8mn+m+n) (8mn-m-n)
= (8mn)^2 - (m+n)^2
= (8mn+m+n) (8mn-m-n)
2007-08-02 5:10 pm
64m^2n^2 - (m+n)^2
--> 記唔記得 a^2 - b^2 = (a+b) (a-b)
64m^2n^2 - (m+n)^2
= (8mn)^2 - (m+n)^2
=(8mn+m+n) (8mn-m-n)
--> 記唔記得 a^2 - b^2 = (a+b) (a-b)
64m^2n^2 - (m+n)^2
= (8mn)^2 - (m+n)^2
=(8mn+m+n) (8mn-m-n)
參考: myself
收錄日期: 2021-04-27 14:59:25
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