✔ 最佳答案
設蜘蛛有x隻, 蜻蜓有y隻, 蟬有z隻。
x + y + z = 18 --- ( 1 )
8x + 6y + 6z = 118
4x + 3y + 3z = 59 --- ( 2 )
( 0 )( x ) + 2y + z = 20
z = 20 - 2y --- ( 3 )
分別代( 3 )入( 1 )和(2 ),
x + y + 20 - 2y = 18
x - y = - 2
y = x + 2 --- ( 4 )
4x + 3y + 3 ( 20 - 2y ) = 59
4x + 3y + 60 - 6y = 59
4x - 3y = - 1 --- ( 5 )
代( 4 )入( 5 ),
4x - 3 ( x + 2 ) = - 1
4x - 3x - 6 = -1
x = 5
4 ( 5 ) - 3y = -1
3y = 21
y = 7
z = 20 - 2 ( 7 ) = 6
所以,
蜘蛛: 5隻
蜻蜓: 7隻
蟬: 6隻