各位知識朋友 , 入黎幫我手 ar !!!
我有幾條數學問題唔識 , 幫手解答 ar ( 數學暑期作業) !!!!!!!!!!!!!!!( 要步驟 )
1.當b=「-3」和c=2時,求下列代數式的值:
(a)b∕3c
(b)c-b
(c)2b+c
(d)4bc
2.當e=「-2」,f=3,g=「-1」時,求下列代數式的值:
(a)efg
(b)-e-(-f)+c
(c)2e-f-g
(d)e+f∕g
各位知識朋友 , 入黎幫我手 ar !!! ( P6升F1-數學暑期作業 ) (14)
2007-08-02 1:49 am
回答 (4)
2007-08-02 2:03 am
✔ 最佳答案
1a. b/3c = -3/3(2) = -3/6 = -1/21b. c-b = 2-(-3) = 2+3 =5
1c. 2b+c = 2(-3) +2 = -6 +2 = - 4
1d. 4bc = 4x(-3) x (2) = - 24
2a. efg = -2x3x (-1) = -6 x -1 = 6
2b. -e-(-f)-g = -(-2)-(-3)+ (-1) = 2+3-1 = 4
2c. 2e-f-g = 2(-2)-3-(-1) = -4-3+1 = -7+1 = -6
2d. e+f/g = -2 + 3/-1 = -2 + (-3) = 2-3 = -1
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參考: me
2007-08-03 1:49 am
我的答案是:
1a)
-3 / 3c
=-1
b)
2 - (-3)
=5
c)
2(-3) +2
=-3
d)
4 x (-3) x2
= -24
2a)
-2 x 3 x (-1)
=5
2b)
-(-2) - 3 - (-1)
=-4
2c)
2(-2) - 3 +1
= - 6
2d)
-2+3/-1
=1
1a)
-3 / 3c
=-1
b)
2 - (-3)
=5
c)
2(-3) +2
=-3
d)
4 x (-3) x2
= -24
2a)
-2 x 3 x (-1)
=5
2b)
-(-2) - 3 - (-1)
=-4
2c)
2(-2) - 3 +1
= - 6
2d)
-2+3/-1
=1
參考: 自己
2007-08-02 1:58 am
-3/6=-1/2
2-(-3)=5
2(2)+(-3)=1
4(2)(-3)=-24
-2x3x-1=6
2+3+c=5+c
-4-3+1=-6
-2+3/-1=-5
2007-08-01 18:00:21 補充：
sor 2b c is-4
2-(-3)=5
2(2)+(-3)=1
4(2)(-3)=-24
-2x3x-1=6
2+3+c=5+c
-4-3+1=-6
-2+3/-1=-5
2007-08-01 18:00:21 補充：
sor 2b c is-4
2007-08-02 1:54 am
1a)-1/2
1b)5
1c)-4
1d)-24
2a)6
2b)4
2c)-6
2d)-1
1b)5
1c)-4
1d)-24
2a)6
2b)4
2c)-6
2d)-1
收錄日期: 2021-04-13 14:04:46
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https://hk.answers.yahoo.com/question/index?qid=20070801000051KK04303