有d數唔識

2007-08-01 1:14 am

回答 (3)

2007-08-01 1:34 am
✔ 最佳答案
|         2x^2 -  x + 1
| X)              x - 2
| ─────────────────────────────────
|  2x^3 -  x^2 +  x
|       - 4x^2 + 2x - 2
| ─────────────────────────────────
|  2x^3 - 5x^2 + 3x - 2

所以答案是 2x^3 – 5x^2 + 3x – 2

|         2x^2      - 3
| X)             2x - 3
| ─────────────────────────────────
|  4x^3        - 6x
|       - 6x^2 +    + 9
| ─────────────────────────────────
|  4x^3 - 6x^2 - 6x + 9

所以答案是 4x^3 – 6x^2 - 6x + 9
2007-08-01 1:33 am
上面好似計錯左..定我計錯?
*=乘
(a).(2x^2-x+1)*(x-2)
=2x^3-4x^2-x^2+2x+x-2
=2x^3-3x^2+3x-2

(b) (2x^2-3)*(2x-3)
=4x^3-6x^2-6x+9
參考: me
2007-08-01 1:24 am
http://img151.imageshack.us/img151/7016/65602882vb2.jpg
其實同普通數字x法一樣
.......2x^2 - x + 1
X)..............x - 2
-----------------------
2x^3 - x^2 + x
........4x^2 - 2x - 2
--------------------------
2x^3 + 3x^2 - x - 2
==============

http://img165.imageshack.us/img165/7118/10259404lx5.jpg
.......2x^2..........- 3
X)................2x - 3
-----------------------------
4x^3 + 0x^2 - 6x
...........6x^2 - 0x + 9
------------------------------
4x^3 + 6x^2 - 6x + 9
===============
參考: 自己


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