F3 INEQUALITIES 一題

2007-07-31 1:31 am
{ 5( x - 3) } /4 + 6 (x - 2) < 5 ( x- 3/4 ) - 26


plz show the steps

回答 (3)

2007-07-31 2:08 am
✔ 最佳答案
{5(x - 3)} /4 + 6(x - 2) < 5(x - 3/4) - 26
{5(x - 3)} + 24(x - 2) < 20(x - 3/4) - 104
5x - 15 + 24x - 48 < 20x - 15 - 104
29x - 63 < 20x - 119
9x < -56
x > -56/9
2007-07-31 6:55 am
{ 5( x - 3) } /4 + 6 (x - 2) < 5 ( x- 3/4 ) - 26
5(x - 3) + 24(x - 2) < 5(4x - 3) - 108
5x - 15 + 24x - 48 < 20x - 15 - 108
29x - 63 < 20x - 123
9x < -60
x < -60/9 = -20/3

2007-07-30 22:58:05 補充:
修正:{ 5( x - 3) } /4 + 6 (x - 2) < 5 ( x- 3/4 ) - 265(x - 3) + 24(x - 2) < 5(4x - 3) - 1045x - 15 + 24x - 48 < 20x - 15 - 10429x - 63 < 20x - 1199x < -56x < -56/9
2007-07-31 3:55 am
[5(x-3)]/4+6(x-2)<5(x-3/4)-26
(5x-15)/4+6x-12<5x-15/4-26
5/4x-15/4+6x-12<5x-15/4-26
5/4x+6x-5x<-15/4-26+15/4
9/5x<-26
x<-26*5/9
x<130/9
x<14又4/9


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