數學的問題.............

1. 7a+9a= 16a
2. 10b-7b+b=4b
3.12b-(14b-5b)=3b
4. 2aX3a=6a
5. 3aXa=3a2 <---2次方
6.a3Xa=a4 <----a既4次方
7. a4Xa5= a20 <---a既20次方
7. 12a/6= 2a
9. (6a)/(2b)=
8.a8/a2= a4

(2)
h=12,k=9

2h-4k= 2x12 - 4x9 = 24-36 = -12

7(h-k)= 7 (12-9) = 7x3 =21

6/5h-3/k= 6/5(12) - 3/9 = 1/10- 1/3 = 1/30 (30分之1)

2007-07-30 17:25:53 補充：
第4題應該係: 6a2 (6a既2次方)

1.7a+9a
=16a
2.10b-7b+b
=4b
3.12b-(14b-5b)
=12b-9b
=3b
4.2aX3a
=6a2
5.3aXa
=3a2
6.a3Xa
=a4
7.a4Xa5
=a9
7.12a/6
=2a
8.a8/a2
=a6
9.(6a)/(2b)
(2)
h=12,k=9
2h-4k
=2(12)-4(9)
=24-36
=-12
7(h-k)
=7(12-9)
=7(3)
=21
6/5h-3/k
=6/5(12)-3/9
=6/60-3/9
=1/10-1/3
=3/30-10/30
=-7/30

1. 7a+9a= 16a
2. 10b-7b+b= 4b
3.12b-(14b-5b)= 3b
4. 2aX3a= 6a2 ( a square not 2)
5. 3aXa= 3a2 (a square not 2)
6.a3Xa= 3a2 ( a square not 2)
7. a4Xa5= 20a2 (a square not 2)
7. 12a/6 = 0.5a
9. (6a)/(2b) = 3a/b
8. a8/a2 = 4
2h-4k= 2(12) - 4(9) = -12
7(h-k)= 7 (12-9) = 21
6/5h-3/k= 6/5(12) - 3/(9) = 1/10 - 1/3 = 3-10/30 = -7/30

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