(A-B)x+B=8x-5
A同B的數值是???
數學:恆等式~1題
2007-07-30 9:41 pm
回答 (3)
2007-07-30 9:59 pm
✔ 最佳答案
(A-B)x+B=8x-5B=-5---------------1
A-B=8--------------2
把1代入2
A-(-5)=8
A=3
2007-07-30 10:15 pm
(A-B)x + B = 8x - 5
Ax - Bx + B = 8x - 5
therefore Ax - Bx = 8x________(3)
B = -5
substitute B = -5 in (3)
Ax - Bx = 8x
Ax - (-5)x = 8x
Ax + 5x = 8x
Ax = 3x
A = 3
Therefore A = 3 , B = -5
(你可以代個ans入原本條式度驗算一下....--我唔知有冇計錯...)
Ax - Bx + B = 8x - 5
therefore Ax - Bx = 8x________(3)
B = -5
substitute B = -5 in (3)
Ax - Bx = 8x
Ax - (-5)x = 8x
Ax + 5x = 8x
Ax = 3x
A = 3
Therefore A = 3 , B = -5
(你可以代個ans入原本條式度驗算一下....--我唔知有冇計錯...)
參考: 自己
2007-07-30 10:11 pm
A-B = 8 and
B=-5
so A-(-5) = 8
A =3
B =-5
B=-5
so A-(-5) = 8
A =3
B =-5
收錄日期: 2021-04-13 18:34:13
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