有關因式分解

2007-07-30 10:53 am
6.a.因式分解x2次+2x+1

b.利用a.的結果,因式分解x2次+y2次+2xy+2x+2y+1

回答 (2)

2007-07-30 6:16 pm
✔ 最佳答案
6a) x^2 + 2x + 1
= (x + 1)^2
b) x^2 + y^2 + 2XY + 2X + 2Y+ 1
= (x + 1)^2 + 2xy + 2y + y^2
= (x + 1)^2 + 2y(x + 1) + y^2
= (x + y + 1)^2

7. 4x^2 + 4xy + y^2
= (2x)^2 + 2(2x)(y) + y^2
= (2x + y)^2
2007-07-30 11:05 am
6a) x^2 + 2x + 1 = (x + 1)^2
b)x^2 + y^2 + 2XY + 2X + 2Y+ 1 = (x + 1)^2 + 2xy + 2y + y^2
= (x + 1)^2 + 2y(x + 1) + y^2 = (x + y + 1)^2

7. 4x^2 + 4xy + y^2 = (2x)^2 + 2(2x)(y) + y^2 = (2x + y)^2

2007-07-30 15:51:58 補充:
下面那一個完全一樣的-.-

2007-08-01 17:08:32 補充:
和我的完全一樣,完全是抄的~
參考: ME


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