英文物理,幚幚手!!

a large bucket of water means a large amount of water

consider E=mcΔT (+ml)
the 500'C horseshoe has definite energy E', c for water is constant

heat loss by horseshoe(E') = heat gain by water

consider a slow stream of water at 20'C,

E'=(specific heat capacity of horseshoe )0.5(500-100) it is a constant

E'=4200m(100-20) + 2260000 m
where m is the mass of water


the question is ridiculous
whether more or less water will be vaporized depends on the mass of a large bucket of water compare to the speed of flow of stream.
"""IF""" the stream flows extemely fast, it is the best way to cool down the horseshoe

luckly, the stream is slow(but no one know how exactly slow it is)

SO we must assume the mass of the large bucket of water is extremely large
and the speed of flow of stream is extremely slow ( I hate this kind of CE questions)

Because more energy is consumed to heat up the large amount of water to 100'C
LESS ENERGY LEFT for vaporizing the water
hence LESS water is vaporized.

The answer is less from (b). Try to think about the reason. Hints: Preservation of energy, Heat Latency.. something like that. these terms have been forgotten..