找規律(數)急...10分

(1)2,3,5,9,17,(33),(65)
(2)2,4,10,28,82,(244), (730)
(3)94,46,22,10,(4),(1)
(4)2,3,7,18,7,(3) ,(2)

2007-07-28 14:12:06 補充：
(1)2＋2^0 = 33＋2^1 = 55＋2^2 = 99＋2^3 = 17因此,第一個答案 = 17＋2^4第二個答案 = 17＋2^4＋2^5

2007-07-28 14:16:16 補充：
(2)2＋2×3^0 = 44＋2×3^1 = 1010＋2×3^2 = 2828＋2×3^3 = 82因此,第一個答案 = 82＋2×3^4第二個答案 = 82＋2×3^4＋2×3^5

2007-07-28 14:18:24 補充：
94÷2－1 = 4646÷2－1 = 2222÷2－1 = 10因此,第一個答案 = 10÷2－1第二個答案 = (10÷2－1)÷2－1

2007-07-28 14:22:39 補充：
(4)講真,我不肯定"2,3,7,18,7,(3) ,(2)"是否正確但除了對稱外,我看不出有其他可能的規律

(1)2,3,5,9,17,(33),(65) 如果....a,b.... - b等於2a減1

(2)2,4,10,28,82,(244),(730) 如果....a,b.... - b等於3a減2

(3)94,46,22,10,(4),(1) 如果....a,b.... - a除2減1等於b

(4)2,3,7,18,7,(?),(?) ~諗唔到, sorry~

1)

2,3,5,9,17,(33),(65)

{2[+1]=3[+2]=5[+4]=9[+8]=17[+16]=33[+32]=65}



2)

2,4,10,28,82,(244), (730)

2 + 2=4
4 + 3 x 2=10
28 + 3 x 18
82 + 3 x 54=244
244 + 3 x 162=730



3)

94,46,22,10,(4),(1)


(4)2,3,7,18,7,(3) ,(2)



/\
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(1.)1+2^(n-1)
(2.)1+3^(n-1)
(3.)2*(47/23/11/5)
(4.)對稱瓜
(1)33,65
(2.)244,730(3.)4,不知道
(4.)3,2

(1)2,3,5,9,17,(33),(65)
(2)2,4,10,28,82,(244), (730)
(3)94,46,22,10,(4),(1)
(4)2,3,7,18,7,(3) ,(2)

(1):
The numbers, starting from 2, is added by 1, 2, 4, 8 ...
i.e.3 = 2+1
5 = 3 + 2
9 = 5 + 4
17 = 9 + 8
so the nest two terms are 33 (17 + 16) and 65 (33 + 32)

(2):
4 = 2 + 2
10 = 4 + 6 = 4 + (3 x 2)
28 = 10 + 18 = 10 + (3 x 6)
82 = 28 + 54 = 28 + (3 x 18)
so the terms are given by adding 3n, where n is the number added by the pervious term
Hence, next 2 terms are 244 (82 + (3 x 54)) and 730 (244 + (3 x 162))

(3):
46 = 94 - 48
22 = 46 - 24 = 46 - (48/2)
10 = 22 - 12 = 46 - (24/2)
so the terms are given by subtracting n/2, where n is the number subtracted by the pervious term
Hence, next 2 terms are 4 (10 - 12/2) and 1 (4 - 6/2)

(4)
I don't know...
Maybe it is 3, 2 (just reversing the order)