Find A and B
x square+Ax=10 identity to (x-2)(x+B)
Express 225 as a product of prime factors
Math Q
2007-07-27 9:02 pm
回答 (2)
2007-07-27 9:14 pm
✔ 最佳答案
x^2+Ax-10 = (x-2)(x+B)x^2+Ax-10 = x^2+Bx-2x-2B
x^2+Ax-10 = x^2+(B-2)x-2B
by the above, we've got A = B-2 and 10 = 2B
as a result B = 5 and A = 3
Express as a product of prime factors
225 = 15 x 15
= 3 x 5 x 3 x 5
= 3 x 3 x 5 x 5
參考: me
2007-07-27 9:25 pm
x² + Ax - 10 = (x - 2)(x + B)
considering constant term,-10 = -2B => B = 5,
considering x term,B - 2 = A => A = 3
225 = 15² = 3 x 3 x 5 x 5
considering constant term,-10 = -2B => B = 5,
considering x term,B - 2 = A => A = 3
225 = 15² = 3 x 3 x 5 x 5
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