加上以下數字,使算式成立
1,2,3,4,5,6,8 (不能重復)
4 x _ + 7 x _ = _ x 9 +_ x 10 + _^2 + _ ^2
4 x _ + 7 x _ = _ x 9 +_ x 10 + _^2 + _ ^2
2007-07-27 6:06 pm
回答 (3)
2007-07-27 6:47 pm
✔ 最佳答案
4 X 6 + 7 X 8 = 4 X 9 + 1 X 10 + 5^2 + 3^2以上都係等於80
2007-07-27 10:53:19 補充：
我上面個個 bb/ 抱抱 跟本睇錯題目佢睇錯左次方 做除定唔知乘
參考: me
2007-07-27 7:25 pm
問題:4 x _ + 7 x _ = _ x 9 +_ x 10 + _^2 + _ ^2
加上以下數字,使算式成立
1,2,3,4,5,6,8 (不能重復)
4 x _ + 7 x _ = _ x 9 +_ x 10 + _^2 + _ ^2
答案:(4 X 6) + (7 X 8) = (4 X 9) +( 1 X 10) +( 5^2) +(3^2)
加上以下數字,使算式成立
1,2,3,4,5,6,8 (不能重復)
4 x _ + 7 x _ = _ x 9 +_ x 10 + _^2 + _ ^2
答案:(4 X 6) + (7 X 8) = (4 X 9) +( 1 X 10) +( 5^2) +(3^2)
2007-07-27 6:34 pm
首先計算程序就系先乘除後加減
4x2 = 8
7x8 = 56 結果得出黎既數 = 8+56 = 64
1x9 = 9
5x10=50
4/2=2
6/2=3 結果得出黎既數 = 9+50+2+3 =64
答案如下：
4 x ( 2 ) + 7 x ( 8 ) = ( 1 ) x 9 + ( 5 ) x 10 + ( 4 ) ^2 + ( 6 ) ^2
4x2 = 8
7x8 = 56 結果得出黎既數 = 8+56 = 64
1x9 = 9
5x10=50
4/2=2
6/2=3 結果得出黎既數 = 9+50+2+3 =64
答案如下：
4 x ( 2 ) + 7 x ( 8 ) = ( 1 ) x 9 + ( 5 ) x 10 + ( 4 ) ^2 + ( 6 ) ^2
收錄日期: 2021-04-23 18:54:32
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