Form . 2 MATHS 恆等式問題10條

2007-07-25 6:46 pm
1 . (x +2)x=Ax^2 + Bx
2. Ax+B=2(x+1)
3. Ax+(A-B)=3x+7
4. (A+B)x-A=-2-1
5. 6(x-2)+10=Ax+B
6. (A-B)x+A = 3 - Bx^2
7. 2Ax-B=9-3x
8. -9x^2+A= 3 - Bx^2
9. 2(A+B)x+1=8x+A
10. 5(Ax+4)=B(x+2)
THX!!!

回答 (2)

2007-07-25 7:02 pm
✔ 最佳答案
1. LHS= X^2+2x
RHS= Ax^2+Bx
comparing coefficients on both sides
A=1,B=2

2.LHS=Ax+B
RHS=2x+2
comparing coefficients on both sides
A=2,B=2

3.LHS=Ax+(A-B)
RHS=3x+7
comparing coefficients on both sides
A=3,B= -4

4.LHS=(A+B)x-A
=Ax+Bx-A
RHS=-2x-1
comparing coefficients on both sides
A=1,B= -3

5.LHS=6x-12+10
=6x-2
RHS=Ax+B
comparing coefficients on both sides
A=6,B= -2


7.LHS= -B+2Ax
RHS= 9-3x
comparing coefficients on both sides
2A= -3,A=- 2/3
B= -9

8.LHS= -9x^2+A
RHS= -Bx^2+3
comparing coefficients on both sides
A=3,B=9

9.LHS=2Ax+2Bx+1
RHS= 8x+A
comparing coefficients on both sides
A=1, B=3

10.LHS=5Ax+20
RHS=Bx+2B
comparing coefficients on both sides
5A=B,B=10
5A=10
A=2,B=10

2007-07-26 18:09:21 補充:
6. (A-B)x A = 3 - Bx^2 LHS=Ax-Bx A RHS= -Bx^2 3 A=3 Ax-Bx=3x-Bx B=3 or Bx^2=0 B=0
2007-07-25 7:07 pm
1.a=1,b=2
2.a=2,b=2
3.a=3,b=7
4.a=-2,b=-1
5.a=6,b=-2
6.a=3,b=?
7.a=9/2,b=3/2
8.a=3,b=9
9.a=4,b=?
10.a=?,b=?


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