if f(x)=log 2x-x
then
f(x+1) -f (x) = ?
ce maths
2007-07-25 4:00 am
回答 (3)
2007-07-25 4:52 am
✔ 最佳答案
f ( x +1 ) = log 2 ( x + 1 ) - ( x + 1 ) f ( x + 1 ) - f ( x ) = log 2 ( x + 1 ) - ( x + 1 ) - log 2x + x
= log 2 ( x + 1 ) - log 2x - 1
= log ( x + 1 ) / x - log 10
= log ( x + 1 ) / 10x
參考: My Maths Knowledge
2007-07-25 11:21 pm
f(x+1)-f(x)=log(2x+2)-x-1-log2x+x
=log[(2x+2)/2x]-1
=log[(x+1)/x]-1
=log(x+1)-logx-1
=log[(2x+2)/2x]-1
=log[(x+1)/x]-1
=log(x+1)-logx-1
2007-07-25 4:04 am
f(x+1) -f (x) = log [2(x+1)-(x+1)] - log 2x-x
收錄日期: 2021-04-23 17:09:19
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