10點------factorization`!

(a)
-8+18p-9p²
=-(9p²-18p+8)
=-(3p-2)(3p-4)
(b)
x(4x-37)-30
=4x²-37x-30
=(4x+3)(x-10)
(c)
15(z+3)²+13(z+3)-2
=[(z+3)+1][15(z+3)-2]
=(z+4)(15z+43)
(d)
2x²+9xyz+4y²z²
=(2x+yz)(x+4yz)

a) you may use quad formular to try it, but remember to check the answer and don't omit the - sign (or simply, cross method if you can see it)
ans: -(3x-2)(3x-4)

b) expand it and do the same as a)
ans: (x-10)(4x+3)

c) should be 15(z+3)²+13(z+3)-2 instead, right?
put z+3=x, u will get 15x²+13x-2
and the ans should be (15x-2)(x+1)
back substitute x=z+3 into the original equation
ans: (15z+43)(z+4)

d) it should not be so easy to look from the polynomial right here at first, you must do it by observation (cross method), you will get the ans
ans: (2x+yz)(x+4yz)

hope u understand how it is done!