8^(3n+1)/4^4n
唔該!
數學題一問
2007-07-23 5:41 pm
回答 (5)
2007-07-24 9:29 am
✔ 最佳答案
Simplify (8^(3n + 1))/(4^4n).(8^(3n + 1))/(4^4n)
= [(2³)^(3n + 1)]/[(2²)^4n]
= [2^(3(3n + 1))]/[2^(2 × 4n)]（∵(x^m)ⁿ = x^mn）
= (2^(9n + 3))/(2^8n)
= 2^(9n + 3 – 8n)（∵(x^m)/(xⁿ) = x^(m – n)）
= 2^(n + 3)
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2007-07-24 12:02 am
您的式子漏了等於什么呀！
例：8^(3n+1)/4^4n = 1
(2x4)^(3n+1)/4^4n = 1
(4^(-n+1))x2 = 1
(8^(-n+1)) = 1
n =0
例：8^(3n+1)/4^4n = 1
(2x4)^(3n+1)/4^4n = 1
(4^(-n+1))x2 = 1
(8^(-n+1)) = 1
n =0
參考: 我的知識
2007-07-23 9:30 pm
What is the question?? To simplify it? 2^(n+3)
2007-07-23 6:09 pm
2^(-5n+1)
2007-07-23 6:04 pm
2^(n+3)
收錄日期: 2021-04-19 20:30:42
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070723000051KK00729