數學題一問

Simplify (8^(3n + 1))/(4^4n).



　(8^(3n + 1))/(4^4n)

= [(2³)^(3n + 1)]/[(2²)^4n]

= [2^(3(3n + 1))]/[2^(2 × 4n)]（∵(x^m)ⁿ = x^mn）

= (2^(9n + 3))/(2^8n)

= 2^(9n + 3 – 8n)（∵(x^m)/(xⁿ) = x^(m – n)）

= 2^(n + 3)
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您的式子漏了等於什么呀！
例：8^(3n+1)/4^4n = 1
　　(2x4)^(3n+1)/4^4n = 1
　　(4^(-n+1))x2 = 1
　　　(8^(-n+1)) = 1
　　　　　　 n =0

What is the question?? To simplify it? 2^(n+3)

2^(-5n+1)

2^(n+3)